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#include <stdio.h>
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#include <limits.h>
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#include <stdlib.h>
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int main(int argc, const char *argv[])
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{
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double no = 0;
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for (int i=0; i<argc; i++) {
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no += atoi(argv[i]) / 1000000;
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}
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if (argc < 2)
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printf("%f\n", no);
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if (argc > 1)
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printf("%.0f\n", no / (argc - 1));
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return 0;
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}
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